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(C) According to the $1^{	ext{st}}$ law of thermodynamics,$\Delta U = q + w$,where $w$ is the work done on the system. If $W$ is the work done by the

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adiabatic

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(C) According to the $1^{	ext{st}}$ law of thermodynamics,$\Delta U = q + w$,where $w$ is the work done on the system. If $W$ is the work done by the system,then $w = -W$. Thus,$\Delta U = q - W$. Given that the internal energy decreases by the same amount as the work done by the system,we have $\Delta U = -W$. Substituting this into the equation: $-W = q - W$. This simplifies to $q = 0$. $A$ process in which there is no heat exchange $(q = 0)$ is known as an adiabatic process.

If the internal energy of an ideal gas decreases by the same amount as the work done by the system,the process is

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